如何能够清除aud脚本？

--//发现自己写的清除aud脚本通用性不好,每次都要修改,写一个通用脚本.而且一些服务器有多个实例的情况.
--//编写脚本如下:

cat /usr/local/bin/purge_oracle_aud.sh

! /bin/bash

purge oracle audit log

odebug=${ODEBUG:-0}

if (( $# < 1 ))
then

echo "arguments is insufficiency , argumentN = oracle_sid N>=1"
exit 1

fi

for i in "$@"
do

if [ -d /u01/app/oracle/admin/${i}/adump/ ]
then
echo
echo "start purge oracle audit ${i} at : " $(/bin/date +'%Y/%m/%d %T') /usr/bin/find /u01/app/oracle/admin/${i}/adump/ -mtime +30 -name "${i}_ora_*.aud" -print -delete
echo "end purge oracle auditwww.cungun.com ${i} at : " $(/bin/date +'%Y/%m/%d %T')
echo else
echo "/u01/app/oracle/admin/${i}/adump/ directory is not exist"
exit 2
fi

done

chmod 700 /usr/local/bin/purge_oracle_aud.sh

--//还是通用性不好,没有利用环境变量$ORACLE_BASE,先暂时这样没时间.

2.加入crontab页游脚本:

cat /etc/cron.d/ntp

34 6 * root /usr/local/bin/purge_oracle_aud.sh dbcndg2 >> /var/log/purge_oracle_aud.log 2>&1
--//每天6:34分执行.

3.修改/etc/logrotate.d/oracle,加入如下:

grep -v "^#" /etc/logrotate.d/oracle

/var/log/purge_oracle_aud.log
{

size=20Mrotate 5copytruncatecompressnotifemptymissingok

}